3.5 Homework

# Hack 1 (Python) - Determine Whether to Go Outside
def should_go_outside(temperature, is_raining):
    """Determines if it's suitable to go outside based on temperature and rain."""
    if temperature < 100 and is_raining:
        return True
    elif temperature > 32 and not is_raining:
        return True
    else:
        return False

# Example Usage
print(should_go_outside(85, True))
print(should_go_outside(50, False))
print(should_go_outside(100, True))
print(should_go_outside(30, False))

# Hack 2 (Python) - Simplified Conditions for Staying Inside
is_raining = True  # Define if it is raining
is_cold = False    # Define if it is cold

# Condition 1: Stay inside if it isn't raining or it isn't cold
stay_inside = not is_raining or not is_cold
print(stay_inside)  # Example Output: True

# Condition 2: Stay inside only if both rain and cold are absent
stay_inside = not is_raining and not is_cold
print(stay_inside)  # Example Output: False

True
True
False
False
True
False

// Hack 1 (JavaScript) - Determine Whether to Go Outside
function shouldGoOutside(temperature, isRaining) {
    // Determines if going outside is appropriate based on the weather
    if (temperature < 100 && isRaining) {
        return true;
    } else if (temperature > 32 && !isRaining) {
        return true;
    } else {
        return false;
    }
}

// Example Usage
console.log(shouldGoOutside(85, true));
console.log(shouldGoOutside(50, false));
console.log(shouldGoOutside(100, true));
console.log(shouldGoOutside(30, false));

// Hack 2 (JavaScript) - Simplified Conditions for Staying Inside
// Condition 1: Stay inside if it's not raining or it's not cold
let stayInside = !isRaining || !isCold;

// Condition 2: Stay inside only if both rain and cold are absent
stayInside = !isRaining && !isCold;

  Cell In[5], line 1
    // Hack 1 (JavaScript) - Determine Whether to Go Outside
    ^
SyntaxError: invalid syntax